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BOJ. Passionate Gang-Ho 2 (11376)

[Link] https://www.acmicpc.net/problem/11376


First method and Second method both works. But you might get TLE with second method because the number of candidates of previous matching(from[r_idx]) is bigger.

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#include <algorithm>
#include <iostream>
#include <vector>
#include <map>
#include <set>
#include <queue>
#include <cstring>
#include <stack>
#include <cmath>
// #include <bits/stdc++.h>
using namespace std;
#define FASTIO ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0)
#define command_param int argc, char *argv[]
#define for0(i, n) for(int i = 0; i < n; i++)
#define for1(i, n) for(int i = 1; i < n; i++)
#define fori(s, e) for(int i = s; i < e; i++)
#define ll long long
#define endl "\n"
#define nulls '\0'
#define dkdk " "
const int MAX = 5e5 + 1;
const int INF = 987654321;

int n, m;
vector<bool> updated;
vector<vector<int>> edge;
vector<int> from;
vector<int> doing;

bool can_match(int l_idx) {
  if(updated[l_idx]) return false;
  updated[l_idx] = true;
  for(int r_idx: edge[l_idx]) {
    if(from[r_idx] == -1 || can_match(from[r_idx])) {
      from[r_idx] = l_idx;
      return true;
    }
  }
  return false;
}

int solve() {
  int cnt = 0;
  /* ---First method--- */
  for0(i, n) {
    for0(iter, 2) {
      updated = vector<bool>(n, false);
      if(can_match(i)) cnt++;
    }
  }
  /* ---Second method--- */
  // for0(iter, 2) {
  //   for0(i, n) {
  //     updated = vector<bool>(n, false);
  //     if(can_match(i)) cnt++;
  //   }
  // }
  return cnt;
}

int main() {
  FASTIO;
  cin >> n >> m;
  edge.resize(n << 1);
  from.resize(m, -1);
  for0(i, n) {
    int in; cin >> in;
    edge[i].resize(in);
    for0(j, edge[i].size()) { cin >> in; edge[i][j] = in - 1; };
  }
  cout << solve();
  return 0;
}
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